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17x-2x^2+20=0
a = -2; b = 17; c = +20;
Δ = b2-4ac
Δ = 172-4·(-2)·20
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{449}}{2*-2}=\frac{-17-\sqrt{449}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{449}}{2*-2}=\frac{-17+\sqrt{449}}{-4} $
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